a+(b+c)=ab+acB)a+(b+c)=b(a+c)C)a+(b+c)=(a+b)+c D)a+0=a=0+a
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a+(b+c)=ab+acB)a+(b+c)=b(a+c)C)a+(b+c)=(a+b)+c D)a+0=a=0+a
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