Question

A,b,c & d are for numbers in the arithmetic progression. Mean of these four number is 20 . The common difference between these number is 6. find product of the first and the last number ?​

Answer 1

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Answer 2

Given:

a,b,c & d are for numbers in the arithmetic progression. The mean of these four numbers is 20. The common difference between these numbers is 6.

To Find:

find the product of the first and the last number?​

Solution:

Arithmetic progression is a sequence in which every consecutive term differs by a common difference, where common difference is denoted by 'd',

In the given case we will take the first term as 'a' and consecutively add 6 in them,

a, a+6, a+12, a+18

So now it is given that the mean of these numbers is 20, put in the formula for mean, we have,

$\frac{a+a+6+a+12+a+18}{4} =20\\4a+36=80\\a=11$

So the first term will be 11 and

the last term will be 11+18=29

so the product of these two will be,

Product=29*11

           =319

Hence, the product will be 319.