Question

a b c and d are four points on a circle AC and BD intersect at a point p such that angle b is equal to 130 degree and angle ACD equal to 20 degree then find angle BAC​

Answer 1

Answer:

BEC+∠DEC=180

∘

(complimentary angles)

130

∘

+∠DEC=180

∘

∠DEC=50

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In ΔDEC -

∠DEC+∠ECD+∠CDE=180

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∠CDE=110

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by theorem of circles -

∠BAC=∠CDE

∴∠BAC=110

∘

Answer 2

Here is the required answer to your question