a b c and d are four points on a circle AC and BD intersect at point o such that angle BAC is equal to 130 degree and Angle ACB is equal to 20 find angle BAC
Answers
Answered by
0
hey you yourself wrote the answer
angle BAC=130°
zdk:
wrong question btw
Answered by
6
Hello mate =_=
____________________________
Solution:
∠BEC+∠DEC=180° (Linear Pair)
⇒∠130°+∠DEC=180°
⇒∠DEC=180°−130°=50° ......(1)
∠DEC+∠DCE+∠BDC=180°
Putting value of ∠DCE and using (1), we get
50°+20°+∠BDC=180°
⇒∠BDC=180°−50°−20°=110°
We also have ∠BDC=∠BAC (Angles in the same segment are equal.)
⇒∠BAC=110°
hope, this will help you.
Thank you______❤
_____________________________❤
Attachments:
Similar questions