Math, asked by anandkumar1751, 3 months ago

A, B, C and D are four salesman in the first month they received a commission of Rs.3200 from their company and divided it in the ratio of 2 : 3 : 4 : 7 in the second month the commission doubled, the amount was doubled in the ratio 3 : 4 : 5 : 4. In the third month the commission tripled when compared to the first month and they shared in the ratio of 4 : 7 : 3: 2 and in the fourth month the commission became half of the previous month and they shared it in the ratio of 4 : 3 : 5 : 4 . What was the average monthly earning of C over the period?

Answers

Answered by AbdulRubSir
1

Answer:

1525

Step wise explanation :-

let the amount divided among them be "x".

Month 1 :-

  • It is divided in the ratio 2x : 3x : 4x : 7x ,then the total of the ratio is 16x.
  • i.e. 2x + 3x + 4x + 7x = 16x.
  • It is given that the first month's commission was 3200. Then,
  • 16x = 3200
  • x = 3200/16
  • x = 200

substitute the value of "x" from the 1st month's ratio

Month 2 :-

  • Ratio :- 3:4:5:4
  • But commission was doubled
  • Hence,3x + 4x + 5x + 4x = 6400
  • 16x = 6400
  • x = 6400/16
  • x = 400

substitute x from the ratio, it will be same.

Month 3 :-

  • commission tripled and ratio was 4:7:3:2
  • 4x + 7x + 3x +2x = 9600
  • 16x = 9600
  • x = 9600/16
  • x = 600

Month 4 :-

  • commission halved than previous month,so new commission is 9600/2 = 4800
  • Ratio = 4:3:5:4
  • 4x + 3x + 5x + 4x = 4800
  • 16x = 4800
  • x = 4800/16
  • x = 300

Now,let's calculate the average of C over the period :-

  • C = month 1+2+3+4/4
  • C = 800+2000+1800+1500/4
  • C = 6100/4
  • C = 1525

Hope it helps

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