Question

A,B,C and D are four towns.B is 30km due East of AC is 30 km due North of AD is 45 km due South of A work out the bearing of B from C

Answer 1

33.7°  West of South   is  bearing of D from B

Step-by-step explanation:

Distance Between B  & C

= √( 30² + 30²)

= 30√1 + 1

= 30√2

= 42.4  km

Angle of  B from C =  Tan⁻¹( 30/30)  =   45°

Bearing of B  From C   =  45° South Of East

or 90 - 45°  = 45°     => 45°  East of South

45°   South-East   is  bearing of B from C

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Answer 2

Answer:

213.7˚

Step-by-step explanation:

tan^-1(45/30)=56.3˚

90˚-56.3˚=33.7˚

180˚+33.7˚=213.7˚