A, B, C and D are points on the circle, centre O. BCE is a straight line. Angle AOC= 108° and angle DCE= 60°. Calculate the values of w, x and y
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A,b,c,d are points on the circle, centre O. BCE is a straight line. Angle AOC=108° and angle DCE=60°. the values of
x°=54°
y°=60°
w°=126°
Stepwise explanation is given below:
- It is given that the angle AOC=108°
and DCE=60°......(1)
- In quadilateral AOCB
AngleAOC=2 angleABC...
( angle at the centre is equal to twice the angle at the circumfrance)
108°=2 angleABC
AngleABC=108/2=54°
- In quadilateral ABCD
Angle x+ angle w=180°
(sum of opposite angles of cyclic quadilateral is 180°)
54+ angle w=180°
Angle w=180-54=126°
- It is given that BCE is a straight line
So, angle DCE+ angle DCB=180°
60°+ angle DCB =180°
angle DCB=180-60=120°
Now, in quadilateral ABCD
- Angle x+angle y+angle w+angleDCB=360°
54°+angle y+126°+120°=360°
Angle y=360-300=60°
So, x°=54°
y°=60°
w°=126°