A,B,C and D are positive integers less than10.A is 3 times B and difference between B and D is 2, C is one less than D.Then which is the smallest?
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A is 3 times B, thus B is smaller than A
B = A/3
So B can be 1,2 or 3 as A is less than 10.
Difference between B and D is 2
D can be either B+2 or B-2.
If B=1 or 2, D will be B+2 (as B-2 is -1 and 0, but we know that D is a positive integer). C will be D-1 or B+1. So B will be smallest.
If B=3, then D will be either 1(B-2) or 5(B+2).
C is one less than D, thus C is smaller than D.
C is 0 or 4. But all are positive. So C is 4.
Hence B(=3) is the smallest.
Thus B is smallest.
B = A/3
So B can be 1,2 or 3 as A is less than 10.
Difference between B and D is 2
D can be either B+2 or B-2.
If B=1 or 2, D will be B+2 (as B-2 is -1 and 0, but we know that D is a positive integer). C will be D-1 or B+1. So B will be smallest.
If B=3, then D will be either 1(B-2) or 5(B+2).
C is one less than D, thus C is smaller than D.
C is 0 or 4. But all are positive. So C is 4.
Hence B(=3) is the smallest.
Thus B is smallest.
durkeshbarath:
how d is 1 or 5
difference between B and D is 2. so D either B+2 or B-2
for B=1 or 2, D is not positive if D=B-2,
didn't understand??
then B will be 3 then how D=5
if D=5 then B-D i.e 3-5=-2 negative
I have edited a bit....see if you can understand..
i've understood. Thanks
you are welcome!!
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