A,B,C and D are the four points on the circle AC and BD intersect at a point such that angle BAC is equal to 130° and Angle BCD is equal to 20° find angle BAC.
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SOLUTION:-
Given:-
- A,B,C and D are the four points on the circle.
- <BAC = 130°
- <BCD = 20°
Need to find:-
- The value of <BAC.
Step by step explanation:
In ∆ DEC,
=> <DEC = <EDC+<DCE [exterior angle property of ∆]
Therefore,
=> <EDC = <BEC - <DCE
=> 180°-70°
=> 110°
Therefore,
=> <BDC = 110°
Now,
=> <BAC = <BDC [angles in the segment of a circle are equal]
Therefore,
=> <BAC = 110°
Hence,angle BAC = 110°.
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