Question

A, B, C and D can complete a piece of work in 6, 8, 12 and 24 days respectively. D, C, A and B work sequentially for 2 days each in the same order. This procedure repeats until the work is completed. Who would be the last person completing the work?

Answer 1

Answer:

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Answer 2

Question:-

A, B, C and D can complete a piece of work in 6, 8, 12 and 24 days respectively. D, C, A and B work sequentially for 2 days each in the same order. This procedure repeats until the work is completed. Who would be the last person completing the work?

Given:-

$\sf\fbox{Let the total work of W}$

Solutions:-

speed of A =W/26

speed of B=W/36

speed of C=W/48

$\sf\fbox{Let's to the work of X day}$

Then,

$\frac{w}{48} \times 4 + \frac{w}{24} \times (x - 3) + \frac{w}{36} \times x = w$

Answer:-

$\implies{solving We get = 15 days}$