Math, asked by Krethik2085, 11 hours ago

A, B, C and D distinct consecutive multiples of 2
• A is represented by 2n where n is a natural number
• E, F, G and H are distinct consecutive multiples of 3
• E is represented by 3n where n is a natural number.
• I is the sum of A and E
• J is obtained by subtracting B from F
• K is the remainder obtained by dividing H by D
• L is twice of two times sum of A and E
A B C D
E F G H
I J K L
Find the values of all the variables if A = 6 (K)

Answers

Answered by kmousmi293
0

Answer:

The values of the variables are:

A = 6, B = 8, D = 12, C = 10, E = 9, F = 12, H = 18, G = 15, I = 15, J = 4, K = 6, L = 60

Step-by-step explanation:

Given that A = 6, we can find the values of the other variables as follows:

Since A = 6, which is represented by 2n, we have:

6 = 2n

n = 3

Therefore, A = 6 represents the number 6, and n = 3.

Since A is the first consecutive multiple of 2, we have:

A = 6

The consecutive multiples of 2 are: 6, 8, 10, 12

Therefore, B = 8, C = 10, and D = 12

Since E is the first consecutive multiple of 3, we have:

E = 3n

E = 3(3)

E = 9

The consecutive multiples of 3 are: 9, 12, 15, 18

Therefore, F = 12, G = 15, and H = 18

Now we can calculate the values of the remaining variables:

I = A + E = 6 + 9 = 15

J = F - B = 12 - 8 = 4

K = H ÷ D (remainder of dividing H by D) = 18 ÷ 12 = 6

L = 2 × (2 × (A + E)) = 2 × (2 × (6 + 9)) = 2 × (2 × 15) = 2 × 30 = 60

So, the values of the variables are:

A = 6, B = 8, D = 12, C = 10, E = 9, F = 12, H = 18, G = 15, I = 15, J = 4, K = 6, L = 60

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