Question

A, B, C and D play a game of cards. A
says to B. "If I give you 8 cards, you
will have as many as C has and I shall
have 3 less than what C has. Also, if I
take 6 cards from C, I shall have twice
as many as D has. If B and D together
have 50 cards, how many cards have
A got?
(a) 40
37
Ch 27
(d) 23
in

Answer 1

Step-by-step explanation:

A will have 23 cards........

Answer 2

If we read given question carefully, we get,

B+8 = C ---(i)

A-8 = C-3 ---(ii)

A+6 = 2D ---(iii)

B+D = 50 ---(iv)

Putting C = A -5 from (ii) into (i), we have :

B+8 = A-5 or A-B = 13 ---(v)

Putting D = 50-B from (iv) and (iii), we have :

A+6 = 100-2B or A+2B = 94 ---(vi)

Solving (v) and (vi), we get

B = 27 and A = 40

pls mark me as braiblist then i will follow u