Question

A=+, b=÷, c=× and d=- then whatis the value of 1/5c2b1/5a1/5d1/10=?

Answer 1

Answer:

21/10

Step-by-step explanation:

Answer 2

Answer:

The value of the given expression is $\frac{9}{50}$.

Step-by-step explanation:

Recall the BODMAS rule,

B - Brackets         O - orders         D - Division                M - Multiplication

A - Addition          S - Subtraction

Consider the expression as follows:

$\frac{1}{5} \ c\ 2\ b\ \frac{1}{5}\ a\ \frac{1}{5}\ d\ \frac{1}{10}$ . . . . . . (1)

where $a,\ b,\ c$ and $d$ denotes the mathematical operations.

It is given that,

$a=+$

$b=\div$

$c=\times$

$d=-$

Substituting the values of $a,\ b,\ c$ and $d$ in the expression (1) as follows:

⇒ $\frac{1}{5} \times 2 \div\ \frac{1}{5}+ \frac{1}{5}- \frac{1}{10}$

Using BODMAS, solve the ÷ operation first as follows:

⇒ $\frac{1}{5} \times \frac{2}{5}+ \frac{1}{5}- \frac{1}{10}$

Now, apply the multiplication rule as follows:

⇒ $\frac{2}{25}+ \frac{1}{5}- \frac{1}{10}$

Add the numbers $2/25$ and $1/5$, we get

⇒ $\frac{2+5}{25}- \frac{1}{10}$

⇒ $\frac{7}{25}- \frac{1}{10}$

Lastly, simplify the expression by subtracting the given terms as follows:

⇒ $\frac{7\times 2-5}{50}$

Since LCM of the numbers $10$ and $25$ is $50$.

⇒ $\frac{14-5}{50}$

⇒ $\frac{9}{50}$

Therefore, the value of the expression $\frac{1}{5} \ c\ 2\ b\ \frac{1}{5}\ a\ \frac{1}{5}\ d\ \frac{1}{10}$ is $\frac{9}{50}$.

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