Question

A, B, C and D together have Rs. 250. the amount with C is twice the amount with B. the amount with A and B together is Rs. 30 less than what D has and C has Rs.20 less than what D has. Find the amount with each of them

Answer 1

Answer:

A=30,B=40,C=80,D=100

Step-by-step explanation:

we know that

A+B+C+D=250 ------------(1)

It is given that

C=2(B) -------------------(2)

A+B=D-30 ‐-----------------(3)

C=D-20 ------------------(4)

now do 3+4

A+B+C=2D-50 ----------------(5)

substitute 5 in 1

2D-50+D=250

3D=250+50

D=300/3

D=100

from 4

C=D-20

=100-20

=80

from 3

A+B=D-30

=100-30

=70

now

B=70-A

from 2

C=2B

C =2[70-A]

80=140-2A

2A=140-80

2A= 60

A=30 B=40

therefore

A=30, B=40 , C=80 ,D=100

Answer 2

Let amount D has = x

Amount C has is = (x-20)

Amount B has is = (x-90)/2

amount with A & B together has 30

less than what D has

$A \: has+ \frac{x - 20}{2} =x+30$

$A \: has = 2 + 30- \frac{x - 20}{2}$

$\frac{2x + 60 - x + 20}{2}$

$\frac{x + 80}{2}$

A/Q

$\frac{x + 80}{2} \frac{x - 20}{2} + x - 20 + x = 250$

$\frac{x + 80 + x - 20 + x - 40 - 2x}{2} = 250$

$5x + 20 = 2 \times 250 = 500$

$5x = 500 - 20 = 480$

$x = \frac{480}{5}$

= 96

So the amount D has = 96

The amount C has = x-20 = 76

The amount B has = x-90/2 = 3

The amount A has = 30-3 = 27

#SP J2