Question

a,b,c are in Ap then prove 1/bc,1/ca,1/ab are in ap

Answer 1

Hey !!!

As you know that the difference between two CONSECUTIVE term are in AP is always same ...so let's us see

1/bc , 1/ca , 1/ab

so .. common difference=t2 - t1

=> 1/ca - 1/bc

=> b - a/abc --------1)

now , second common difference = t3 - t1

=> 1/ab - 1/ ca

=> c - b /abc ------2)

after looking both equation we got these are not equal to each other so it is not in an AP

hope it helps !!!

@Rajukumar111