Question

A, B, C are interior angle of triangle ABC. prove that cosec A+B/2=sec c/2

Answer 1

Answer:

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Answer 2

A B and C are interior angle so their sum is 180° A +B+ C = 180 , B+A= 180 - C , Half on both side B+A/2 = 90° - C/2. Cosec(B+A/2) = Cosec (90°- C/2). Cosec(B+A/2) = Sec(C/2). (Because Cosec(90°- theta) = sec theta. Hence its prooved