Question

A b c are interior angles of triangle abc prove that cosec a + b by 2 is equal to 60 by 2

Answer 1

Answer:

Weknowthat,InΔABC,

A+B+C=180°[anglesumproperty]

⇒A+B=180°−C

⇒(A+B)/2=(180°−C)/2

=(A+B)/2=90°−C/2

⇒cosec(A+B)/2=cosec(90°−C/2)  [as,cosec(90°−θ)=secθ]

⇒cosec(A+B)/2=sec(C/2)

Step-by-step explanation: