Question

a, b, c,.. are (m+1) distinct prime numbers. The number of factors of abc...is solve by permutation and combination ​

Answer 1

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‘abc’ has exactly 3 factors, so ‘abc’ should be square of a prime number. (This is an important inference, please remember this).

Any number of the form paqbrc will have (a + 1) (b + 1) (c + 1) factors, where p, q, r are prime. So, if a number has 3 factors, its prime factorization has to be p2.

‘abcabc’ = ‘abc’ * 1001 or abc * 7 * 11 * 13 (again, this is a critical idea to remember)

Now, ‘abc’ has to be square of a prime number. It can be either 121 or 169 (square of either 11 or 13) or it can be the square of some other prime number.

When abc = 121 or 169, then ‘abcabc’ is of the form p3q1r1 1, which should have 4 * 2 * 2 = 16 factors.

When ‘abc’ = square of any other prime number (say 172 which is 289) , then ‘abcabc’ is of the form p1q1r1s2 , which should have 2 * 2 * 2 * 3 = 24 factors

So, ‘abcabc’ will have either 16 factors or 24 factors.

Hence the answer is 16 factors or 24 factors.

Choice C is the correct answer.

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