Question

a, b, c are non vectors. prove four points are coplanar. 6a+2b-c 2a-b+3c-(4)-a+2b-4c -12a-b-3c​

Answer 1

Step-by-step explanation:

Given A, b, c are non vectors. prove four points are coplanar. 6a+2b-c  2a-b+3c  -a+2b-4c  -12a-b-3c

• So let A = 6a + 2b – c
•          B = 2a – b + 3c
•          C = - a + 2b – 4c
•          D = - 12a – b – 3c
• Now we have the vectors, So  
• Vector AB = - 4a – 3b + 4c
•  Vector BC = - 3a + 3b – 7c
• Vector CD = - 11a – 3b + c
• Now we need to find the determinant of the following. So we have
•                            -4             - 3          4
•                             -3               3        -7
•                             -11           -3          1
• So – 4(3 – 21) – (-3)(-3 – 77) + 4(9 – (-33))
•       -4(-18) + 3(- 80) + 4(42)
•         72 – 240 + 168
•           240 – 240
•                 0
• So AB, BC and CD are coplanar
• So the points A,B,C and D are also coplanar.

Reference link will be

https://brainly.in/question/29659531

Answer 2

Step-by-step explanation:

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