a , b, c are points on circle and tangent at c meetsBA produced at T the given that angle ATC is equal to 36 degree and Angle ACT is equal to 46 degree calculate the angle subtended by a b at the centre of a circle
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Answer:
96°
Step-by-step explanation:
∠ACT=46°,∠ATC=36°
∴∠CAT=180°−(46°+36°)
= 180°−82° = 96°
∴CAB=180∘−96∘=84°
Now, ∠ABC=∠ACT=46°
[angles made in alternate segments]
∴∠BCA=180°−(∠ABC+∠CAB)
= 180°−(46°+84°)=48°
∴∠BOA=2×∠BCA=2×48°=96°
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