Question

A,B,C are the interior angles of triangle ABC,then cosec(A+B/2)=?

Answer 1

Step-by-step explanation:

A+B+C=180degree

A+B=180 - C

cosec(180-C/2)

=cosec(180/2-C/2)

=cosec(90- C/2)

[we know that cosec(90-A)=secA]

so. cosec(90-C/2)

= sec(C/2)