[ A,B,C are the sets of letters needed to spell the words STUDENT,PROGKESS and CONGRUENT respectively.Then n(A uu(B nn C)) is equal to ]
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Set A contain {C,o,l,e,g} 5 letters
Set B contian {m,a,r,i,g,e} 6 letters
Set C contain {l,u,a,g,e} 5 letters
now (BUC)={m,a,r,i,g,e,l,u}
and [A-(BUC)]={c,o}
(subtract the letter containing in a (BUC) from SET A)
NOW second part
A-B={c,o,l}
A-c={c,o}
now intersection of these two are
[(A-B)n (A-C)]={c,o}
so therefore
we get
[A-(BUC)]=[(A-B)n(A-c)].
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