a,b,c are the zero polynomials of 2x^3-3x^2+4x+5. Find the value of (1+a)(1+b)(1+c)
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If a,b,c are the zeroes of p(x) then :-
a+b+c = - coefficient of x^2/coefficient of x^3
=-(-3)/2
=3/2
Now , abc = - constant term / coefficient of x^3
=-5/2
Now , (1/a)(1/b)(1/c)
=1/abc. (abc=-5/2)
=1/(-5/2)
=-(2/5)
Answer :-The value of (1/a)(1/b)(1/c) is -2/5
If you find it helpful please mark it as brainliest....
a+b+c = - coefficient of x^2/coefficient of x^3
=-(-3)/2
=3/2
Now , abc = - constant term / coefficient of x^3
=-5/2
Now , (1/a)(1/b)(1/c)
=1/abc. (abc=-5/2)
=1/(-5/2)
=-(2/5)
Answer :-The value of (1/a)(1/b)(1/c) is -2/5
If you find it helpful please mark it as brainliest....
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