Math, asked by SudiptoDhar, 1 year ago

a,b,c are the zero polynomials of 2x^3-3x^2+4x+5. Find the value of (1+a)(1+b)(1+c)


Hetarth4: Is it correct ?
Hetarth4: it is correct
SudiptoDhar: yeah

Answers

Answered by Hetarth4
2
If a,b,c are the zeroes of p(x) then :-

a+b+c = - coefficient of x^2/coefficient of x^3
=-(-3)/2
=3/2

Now , abc = - constant term / coefficient of x^3
=-5/2

Now , (1/a)(1/b)(1/c)

=1/abc. (abc=-5/2)

=1/(-5/2)

=-(2/5)

Answer :-The value of (1/a)(1/b)(1/c) is -2/5

If you find it helpful please mark it as brainliest....

Hetarth4: Thanks
SudiptoDhar: i think you should check it once more
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