A,B,C are three angles of a triangle. If A-B = 15 degree and B-C=30 degree, then find the angles
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Answered by
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A+B+C = 180°--------(5)(Angle sum property of triangle)
given
A-B = 15°------(1)
B-C = 30--------(2)
Add equation 1 and 2 to eliminate B fro equation
A-B+B-C = 15° + 30°
A-C = 45°-------(3)
then ,
B + C = 180 - A---------from equation (5)
Adding equation 3 and 1
2A-(B+C) = 60
2A-(180-A) = 60
A = 80°
From equation 3
A-C = 45
C = 80-45
C = 35
From equation 2
B-C = 30
B = 30+C
B = 65
A = 80°
B = 65°
C = 35°
If it helped You please Mark it brainliest. :)
given
A-B = 15°------(1)
B-C = 30--------(2)
Add equation 1 and 2 to eliminate B fro equation
A-B+B-C = 15° + 30°
A-C = 45°-------(3)
then ,
B + C = 180 - A---------from equation (5)
Adding equation 3 and 1
2A-(B+C) = 60
2A-(180-A) = 60
A = 80°
From equation 3
A-C = 45
C = 80-45
C = 35
From equation 2
B-C = 30
B = 30+C
B = 65
A = 80°
B = 65°
C = 35°
If it helped You please Mark it brainliest. :)
Answered by
0
Answer:
Above answer is correct
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