Question

a,b,c are three collinear points and a,b,c are the tangents from A,B,C to a given circle,then a²BC+b²CA+c²AB+BC-CA-AB=0​

Answer 1

Answer:

Step-by-step explanation:

Maths

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If a,b,c are all non-zero and a+b+c=0, prove that  

bc

a  

2

 

​  

+  

ac

b  

2

 

​  

+  

ab

c  

2

 

​  

=3

Medium

Answer

Given,  

a+b+c=0

or, a+b=−c

cubing both sides we get,

(a+b)  

3

=−c  

3

 

a  

3

+b  

3

+3ab(a+b)=−c  

3

     [∵(a+b)  

3

=a  

3

+3a  

2

b+3ab  

2

+b  

3

]

a  

3

+b  

3

−3abc=−c  

3

  a+b=−c]

a  

3

+b  

3

+c  

3

 

Now,

bc

a  

2

 

​  

+  

ac

b  

2

 

​  

+  

ab

c  

2

 

​  

 

=  

abc

a  

3

+b  

3

+c  

3

 

​  

 

=3.

Answer 2

Step-by-step explanation:

Solution of this question