a, b, c are three consecutive numbers then find the log 1 + AC base b value
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Let a = x, then b = x + 1 and c = x + 2
1 + ac = 1 + (x)(x + 2)
= 1 + x^2 + 2x
= (x + 1)^2 so,
log (1 + ac)
= log (x + 1)^2
= 2 log (x + 1)
= 2 log (b).
I AM NOT SURE ABOUT THE . SORRY IF U FIND ANY MISTAKE
1 + ac = 1 + (x)(x + 2)
= 1 + x^2 + 2x
= (x + 1)^2 so,
log (1 + ac)
= log (x + 1)^2
= 2 log (x + 1)
= 2 log (b).
I AM NOT SURE ABOUT THE . SORRY IF U FIND ANY MISTAKE
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