Question

A, B, C are three consecutive
points on a line then?
[1] AB+ BC = AC
Gi] Area of A ABC is o
Be + AC = AB
(iv) i and ii​

Answer 1

Let A, B, and C be three distinct points of a line, with the respective coordinates x, y, and z. If x < y < z, then A-B-C.

Proof, By the ruler postulate:

AB = |y-x|

BC = |z-y|

AC = |z-x|.

But y-x is positive because x < y; similarly, z-y and z-x are positive. So:

AB = y-x

BC = z-y

AC = z-x

Finally:

AB + BC = (y - x) + (z - y)

= z-x

=AC.

Since AB + BC = AC, A-B-C by the definition of between.If A, B and C are three points on a line, and B lies between A and C.

Answer 2

Refer above!!

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