Question

A, B, C are three cups having capacities of 120, 180 and 200 cc respectively which are completely filled with
211
tea of three different varieties. They are all mixed in a separate vessel of capacity more than that of A, B, C
taken together, and then the mixture is poured successively into A, B, C. Then how much (in cc) of A and B's
tea will be there in C?​

Answer 1

Given :- A, B, C are three cups having capacities of 120, 180 and 200 cc respectively which are completely filled with tea of three different varieties. They are all mixed in a separate vessel of capacity more than that of A, B, C taken together, and then the mixture is poured successively into A, B, C. Then how much (in cc) of A and B's tea will be there in C ?

Solution :-

given that, all cup are completely filled with tea of three different varieties.

So,

→ Tea in cup A = 120cc

→ Tea in cup B = 180cc

→ Tea in cup C = 200cc

now, all three cups mixed in a separate vessel .

Than,

→ Ratio of varieties of tea in vessel = A : B : C = 120 : 180 : 200 = 6 : 9 : 10 .

Now, again the mixture is poured successively into A, B, C.

Than, we can conclude that, Now, mixture has Ratio of varieties of tea in 6 : 9 : 10.

Therefore,

→ In C , quantity of A = 200 * (6/25) = 48 cc.

→ In C, quantity of B = 200 * (9/25) = 72 cc.

Hence, quantity of A and B in C are 48 cc and 72 cc respectively .

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Answer 2

Answer:

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