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A, B, C are three cups having capacities of 120, 180 und 200 ce respectively which are completely filled with
tea of three different varieties. They are all mixed in a separate vessel of capacity more than that of A, B,C
taken together, and then the mixture is poured successively into A, B, C. Then how much (in cc) of A and B's
tea will be there in C?
Answers
Given :- A, B, C are three cups having capacities of 120, 180 and 200 cc respectively which are completely filled with tea of three different varieties. They are all mixed in a separate vessel of capacity more than that of A, B, C taken together, and then the mixture is poured successively into A, B, C. Then how much (in cc) of A and B's tea will be there in C ?
Solution :
given that, all cup are completely filled with tea of three different varieties.
So,
→ Tea in cup A = 120cc
→ Tea in cup B = 180cc
→ Tea in cup C = 200cc
now, all three cups mixed in a separate vessel .
Than,
→ Ratio of varieties of tea in vessel = A:B:C = 120 :180: 200 = 6:9:10.
Now, again the mixture is poured successively into A, B, C.
Than, we can conclude that, Now, mixture has Ratio of varieties of tea in 6 : 9 : 10.
Therefore,
→ InC, quantity of A = 200 * (6/25) = 48 cc.
→ In C, quantity of B = 200 * (9/25) = 72 cc.
Hence quantity of A and B in C are 48 cc and 72 cc respectively .
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