A, B, C are three distinct natural numbers less
than 11. The arithmetic mean of A and B is 9 and
the geometric mean of B and C is 6√2.
What are
the values of A, B and C,
respectively?
Answers
Answered by
3
Step-by-step explanation:
given ap of a and b is 9
a+b/2=9
a+b=18
gm of b and c is 6√2
√bc=6√2
squaring
bc=36×2=72
a<11,b<11,c<11
Answered by
1
Answer:
a < 11 , b < 11 , c < 11
Step-by-step explanation:
giving ap of a and b is : 9
a+b/2=9
a+b = 18
gm of b and c is : 6_/ 2
_/bc = 6_/ 2
squaring
bc = 36 × 2 = 72
a < 11 , b < 11 , c < 11
hope it's helpful for you
Similar questions