A, B, C are three distinct natural numbers less
than 11. The arithmetic mean of A and B is 9 and
the geometric mean of B and C is 672. What are
the values of A, B and C, respectively?
8, 10,9
a.
8, 9, 10
b.
10, 8, 9
C.
d. 10, 9,8
Answers
Step-by-step explanation:
abc is three digit numbers.
abc is three digit numbers.⇒ 2b+c=bc
abc is three digit numbers.⇒ 2b+c=bc⇒ b+c=2bc
abc is three digit numbers.⇒ 2b+c=bc⇒ b+c=2bcPut c=0 b+0=0 ⇒b=0
abc is three digit numbers.⇒ 2b+c=bc⇒ b+c=2bcPut c=0 b+0=0 ⇒b=0 c=1 b+1=2b ⇒b=1
abc is three digit numbers.⇒ 2b+c=bc⇒ b+c=2bcPut c=0 b+0=0 ⇒b=0 c=1 b+1=2b ⇒b=1 c=2 b+2=4b ⇒b=32
abc is three digit numbers.⇒ 2b+c=bc⇒ b+c=2bcPut c=0 b+0=0 ⇒b=0 c=1 b+1=2b ⇒b=1 c=2 b+2=4b ⇒b=32 .
abc is three digit numbers.⇒ 2b+c=bc⇒ b+c=2bcPut c=0 b+0=0 ⇒b=0 c=1 b+1=2b ⇒b=1 c=2 b+2=4b ⇒b=32 . .
abc is three digit numbers.⇒ 2b+c=bc⇒ b+c=2bcPut c=0 b+0=0 ⇒b=0 c=1 b+1=2b ⇒b=1 c=2 b+2=4b ⇒b=32 . . Only c=0,b=0
abc is three digit numbers.⇒ 2b+c=bc⇒ b+c=2bcPut c=0 b+0=0 ⇒b=0 c=1 b+1=2b ⇒b=1 c=2 b+2=4b ⇒b=32 . . Only c=0,b=0 and c=1,b=1
abc is three digit numbers.⇒ 2b+c=bc⇒ b+c=2bcPut c=0 b+0=0 ⇒b=0 c=1 b+1=2b ⇒b=1 c=2 b+2=4b ⇒b=32 . . Only c=0,b=0 and c=1,b=1 and a=1,2,3,4,5,6,7,8,9
abc is three digit numbers.⇒ 2b+c=bc⇒ b+c=2bcPut c=0 b+0=0 ⇒b=0 c=1 b+1=2b ⇒b=1 c=2 b+2=4b ⇒b=32 .
Answer:
ANSWER
abc is three digit numbers.
⇒ 2b+c=bc
⇒ b+c=2bc
Put c=0 b+0=0 ⇒b=0
c=1 b+1=2b ⇒b=1
c=2 b+2=4b ⇒b=32
.
.
Only c=0,b=0
and c=1,b=1
and a=1,2,3,4,5,6,7,8,9
⇒ 9×2×1 If [b=0→c=0b=1→c=1]
⇒ Total =9×2×1=18