Question

a,b,c are three non-zero digits.The sum of all numbers formed by these three digit is always divisible by
a)a+b+c
b)222,
c)9(a+b+c)​

Answer 1

(c) The number will always be divisible by 9(a+b+c).

Answer 2

Answer:

Step-by-step explanation:

Assume a=2

b=3

c=4

According to the question

2+3+4=9

Therefore 9 is divisible by a+b+c =9

Hence 9/9=1