Math, asked by sricharani27, 2 days ago

A,B,c are three points on circle the centre is zero and every point is equal distance others two points find angle AOB​.Plz answer fastly

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Answered by Equuleus
1

Since A B C are equidistant from each other, then △ABC is an equilateral triangle

So all of its angles are 60°

Now, AO = BO = CO = radius of circle

In the triangles △AOB, △BOC, △COA, we have AO = BO, BO = CO, CO = AO

So, △AOB, △BOC, △COA are isosceles triangles,

But, in these three triangles, AB = BC = CA, so they are congruent to each other.

Therefore, ∠AOB = ∠BOC = ∠COA
Also, these three angles form a circle, so they must add up to 360

So, ∠AOB + ∠BOC + ∠COA = 360

=> 3(∠AOB) = 360
∠AOB = 120

Hope this helped!

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