Question

a, b, c are three real numbers such that

a + b + c = 7, a2

+ b2

+ c

2

= 35 and

a

3

+ b3

+ c

3

= 151. Find the value of abc.

Answer 1

...............................

Answer 2

Hey

Here is ur answer

We know that

(a+b+c)2= a2+ b2+c2 +2(ab+bc+ca)

(7)2=35+2(ab+bc+ca)

49-35/2= ab+bc+ca

14/2= ab+bc+ca

ab+bc+ca=7

Now

a3+b3+c3-3abc= (a+b+c)[a2+b2+c2-(ab+bc+ca)]

151-3abc=7[35-7]
151-3abc=7*28
151-3abc= 196

-3abc=45

abc= -15