a, b, c are zeroes of cubic polynomial x3 - 2x2 +qx -r. If a + b = 0 then show that 2q = r.
Answers
Answered by
5
Answer:
(x-a)(x-b)(x-c)=0
x^3-(a+b+c)x^2+(ab+bc+ca)x-abc=0
comparing
a+b+c=2 but a+b=0
c=2
ab+bc+ca=q
ab+c(a+b)=q
ab=q
abc=r(on comparing)
2q=r
Similar questions