a+b-c
B)
a+b
b+c-
b+c-a
c+c-b
92 a+b+c #0, then prove that a=b=
ca
(If a+b=0
b+c-1 = ctc-b
and a+b+c #0, 2014 a=b=c)
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Answer:
Step-by-step explanation:
we know that a³ + b³ + c³ - 3abc= (a + b + c) (a² + b² + c² - ab - bc - ca)
If (a+b+c) = 0 , then a³ + b³ + c³ = 3abc
Also c = - a - b
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