a(b-c) - b(c-a) – c(a-b)
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Question:
a(b-c) - b(c-a) – c(a-b)
Solution:
= a(b-c) - b(c-a) – c(a-b)
= ab - ac - bc + ab - ac + bc
= ab + ab - ac - ac - bc + bc
= 2ab - 2ac - 0
= 2ab - 2ac
Answers: 2ab - 2ac
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