Question

a(b-c) +b(c-a) +c(a-b).​

Answer 1

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a(b-c)+b(c-a)+c(a-b)

=ab-ac+bc-ab+ac-bc

=0

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Answer 2

a*(b-c) + b*(c-a) + (a-b)
Now,
(ab-ac) + (bc-ba) + (ca-cb). After puting same values aside,
ab-ba-ac+ca+bc-cb
Everything cutted so, 0 is the answer





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