a (b-c)+b (c-a)+c (a-b)
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2
=ab-ac+bc-ab+ac-bc
=ab-ab+bc-bc+ac-ac
=0+0+0
=0
=ab-ab+bc-bc+ac-ac
=0+0+0
=0
tanishq2436:
Correct answer......
yes
I also know.
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Answered by
2
a(b-c)+b(c-a)+c(a-b)
= ab- ac + bc - ba + ca - cb
= ab - ab -ac + ac +BC -cb
= 0
is the answer
= ab- ac + bc - ba + ca - cb
= ab - ab -ac + ac +BC -cb
= 0
is the answer
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