a(b-c) -b(c-a) -c(a-b)
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a(b-c) -b(c-a) -c(a-b)
=ab-ac-bc+ab-ac+bc
=2ab-2ac
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anujyadavdagar41:
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Answered by
5
a(b-c)-b(c-a)-c(a-b)
ab-ac-bc+ab-ac+bc
2ab-2ac
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