Math, asked by as1037728, 3 months ago

(a+b+c)(b+c-a) (c+a-b) (a+b-c) formula is (a^2-b^2)=a+b a-b​

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Answered by suvarnahakke1
1

Answer:

"(a+b+c) (b+c-a) (c+a-b) (a+b-c)

Several use of number property arrangements allows the advantage of Difference of Two Squares.

(a+b+c) (-a+b+c) (a-b+c) (a+b-c)

(a+b+c) ( a+b-c) (-a+b+c) (a-b+c)

( (a+b)+c) ( (a+b)-c) (-1)* ( (a-b)-c) ( (a-b)+c)

((a+b)^2-c^2) (-1)* ( (a-b)^2-c^2)

(a^2+2ab+b^2-c^2) (-1) *(a^2-b^2-c^2)

(-1) * (a^2+2ab+b^2-c^2) (a^2-2ab +b^2-c^2)

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