Question

a(b-c) +b(c-a) +c(a-b) is eqal to​

Answer 1

$\rm{a\left(b-c\right)+b\left(c-a\right)+c\left(a-b\right)=ab-ac+b\left(c-a\right)+c\left(a-b\right)}$

$\longrightarrow\rm{a\left(b-c\right)+b\left(c-a\right)+c\left(a-b\right)=ab-ac+bc-ab+c\left(a-b\right)}$

$\longrightarrow\rm{a\left(b-c\right)+b\left(c-a\right)+c\left(a-b\right)=ab-ac+bc-ab+ac-bc}$

$\longrightarrow\rm{a\left(b-c\right)+b\left(c-a\right)+c\left(a-b\right)=ab-ab-ac+ac+bc-bc=0}$