Math, asked by aaron8566, 9 months ago

(a-b-c)-bc factorise​

Answers

Answered by reeddhimondal
0

Answer:

(a-b-c)-bc

=>a-b-c-bc

Answered by BhaskarGamer
1

Step-by-step explanation:

How do you factorize 1+a+b+c+ab+bc+CA+abc?

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1 + a + b + c + ab + bc + ca + abc

Just rejig things

= 1 + a + b + ab + c + ca + bc + abc

= 1*(1 + a) + b*(1 + a) + c*(1 + a) + bc*(1 + a)

= (1 + a) * (1 + b + c + bc)

= (1 + a) * {1*(1 + b) + c*(1 + b)}

= (1 + a) * (1 + b) * (1 + c).

Can you factorize this: {1+a+b+c+ab+bc+CA+abc}?

What are the factors of:1+a+b+c+ab+bc+ca+abc?

How do you factorize x ⁴+x²+1?

How can I factorize x²+x–1?

How do I factorize 1 (1-ab) +b (ab-1)?

1+a+b+c+ab+bc+ca+abc

a+ab+ac+abc+bc+b+c+1

a(1+b+c+bc)+bc+b+c+1

(1+b+c+bc)(a+1)

(1+ c + b(1+c))(a +1)

(1+c) (1+b) (1+a)

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1+a+b+c+ab+bc+ca+abc

=a+ab+ac+abc + b+c+bc+1

= a + a(b+c+bc) +(b+c+bc) +1

= a(b+c+bc+1) + (b+c+bc+1)

= (a+1)(b+c+bc). Answer.

1+a+b+c+ab+bc+ca+abc=(1+a)+(b+ab)+(c+ca)+(bc+abc)

=(1+a)+b(1+a)+c(1+a)+bc(1+a)

=(1+a)(1+b+c+bc)

=(1+a)([(1+b)+c(1+b)]

=(1+a)(1+b)(1+c)

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