a b c be three non zero vectors .if a.(b×c)=0 and b and c are not parallel..then prove a =mb +nc where m and n are some scalars.
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Since, a+2b is collinear with c
a+2b=mc...(i)
Since b+3c is collinear with a
b+3c=na.....(ii)
Myltiplying Eq(ii) by 2 and subtracting Eq.(ii) from Eq.(i), we get
a−bc=mc−2na
On comparing, we get
m=−6;n=−
2
1
From Eq.(i), we have
a+2b=−6c
⇒a+b+6c=0
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