(a+b+c)
c = 0, then the value of
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Given a + b + c = 0 ⇒ a3 + b3 + c3 = 3abc → (1) Consider, (a2/bc) + (b2/ca) + (c2/ab) = (a3 + b3 + c3)/abc = 3abc/abc = 3
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