Question

a(b-c) + c(a-b) + b(c-a)​

Answer 1

Answer:

Is 0

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Step-by-step explanation:

a(b-c)+c(a-b)+b(c-a)

=ab-ac+ac-bc+bc-ac

=0

Answer 2

According to the information provided in the preceding question,

The supplied value is as follows:

a(b-c) + c(a-b) + b(c-a)​ is the provided question.

We have to find the value of the above equation.

Here we have to use the BODMAS rule.

Thus, solving the given equation we get,

$=a(b-c)+c(a-b)+b(c-a)\\=ab-ac+ac-bc+bc-ab$

Making similar terms one side we get,

$=ab-ab-ac+ac-bc+bc$

$=0$

Hence after solving we get the remaining value as 0.