A,B,C can do a piece of work in 10,12 and25days respectively.After3 days,B left the work In how many days,the remaining work will be completed by both A and C together?
Answers
Answer:
2.3 days
Step-by-step explanation:
Take L.C.M of A,B and C I.e 10, 12 and 25
will get 300
Consider total work as 300 units to be Completed
To know individual work units capacity of A,B and C divide 300 by individual values given
A = 300 / 10 = 30 units per day
B = 300/ 12= 25 units per day
C= 300/25 = 12 units per day
Total work units of A,B and C is 30+25+12= 67 units
So for 3 days all will work together,
In 3 days the amount of work completed would be 3×67= 201 units
Subtract it from total units of work
300-201 = 99 units of work is remaining
B left the work, so 99 units of work will b carried out by A and C
Work unit capacity of A and C is 30 + 12= 42 units per day
Divide Remaining work by 42,
99/42 = 2.3 days
Therefore the remaining work will be completed by both A and C is 2.3 days