Question

a b c can do a piece of work in 10 days 12days and 15 days respectively how long will they take to will they take to finish it if they work together?​

Answer 1

Step-by-step explanation:

A’s one day’s work = 1/10

A’s one day’s work = 1/10B’s one day’s work = 1/12

A’s one day’s work = 1/10B’s one day’s work = 1/12C’s one day’s work = 1/15

A’s one day’s work = 1/10B’s one day’s work = 1/12C’s one day’s work = 1/15A, B and C’s one day’s work = 1/10 + 1/12 + 1/15

A’s one day’s work = 1/10B’s one day’s work = 1/12C’s one day’s work = 1/15A, B and C’s one day’s work = 1/10 + 1/12 + 1/15= (6 + 5 + 4)/60 = 15/60 = ¼

A’s one day’s work = 1/10B’s one day’s work = 1/12C’s one day’s work = 1/15A, B and C’s one day’s work = 1/10 + 1/12 + 1/15= (6 + 5 + 4)/60 = 15/60 = ¼Let the work completed in x days

A’s one day’s work = 1/10B’s one day’s work = 1/12C’s one day’s work = 1/15A, B and C’s one day’s work = 1/10 + 1/12 + 1/15= (6 + 5 + 4)/60 = 15/60 = ¼Let the work completed in x days∴ A’s 2 days work + B’s (x – 3) days work + C’s x days work = 1

A’s one day’s work = 1/10B’s one day’s work = 1/12C’s one day’s work = 1/15A, B and C’s one day’s work = 1/10 + 1/12 + 1/15= (6 + 5 + 4)/60 = 15/60 = ¼Let the work completed in x days∴ A’s 2 days work + B’s (x – 3) days work + C’s x days work = 1⇒ 2 × (1/10) + (x – 3) × 1/12 + x × (1/15) = 1

A’s one day’s work = 1/10B’s one day’s work = 1/12C’s one day’s work = 1/15A, B and C’s one day’s work = 1/10 + 1/12 + 1/15= (6 + 5 + 4)/60 = 15/60 = ¼Let the work completed in x days∴ A’s 2 days work + B’s (x – 3) days work + C’s x days work = 1⇒ 2 × (1/10) + (x – 3) × 1/12 + x × (1/15) = 1⇒ 1/5 + (x -3)/12 + x/15 = 1

A’s one day’s work = 1/10B’s one day’s work = 1/12C’s one day’s work = 1/15A, B and C’s one day’s work = 1/10 + 1/12 + 1/15= (6 + 5 + 4)/60 = 15/60 = ¼Let the work completed in x days∴ A’s 2 days work + B’s (x – 3) days work + C’s x days work = 1⇒ 2 × (1/10) + (x – 3) × 1/12 + x × (1/15) = 1⇒ 1/5 + (x -3)/12 + x/15 = 1(12 + 5x – 15 + 4x = 60)/60

A’s one day’s work = 1/10B’s one day’s work = 1/12C’s one day’s work = 1/15A, B and C’s one day’s work = 1/10 + 1/12 + 1/15= (6 + 5 + 4)/60 = 15/60 = ¼Let the work completed in x days∴ A’s 2 days work + B’s (x – 3) days work + C’s x days work = 1⇒ 2 × (1/10) + (x – 3) × 1/12 + x × (1/15) = 1⇒ 1/5 + (x -3)/12 + x/15 = 1(12 + 5x – 15 + 4x = 60)/60(L.C.M of 5, 12, 15 = 60)

A’s one day’s work = 1/10B’s one day’s work = 1/12C’s one day’s work = 1/15A, B and C’s one day’s work = 1/10 + 1/12 + 1/15= (6 + 5 + 4)/60 = 15/60 = ¼Let the work completed in x days∴ A’s 2 days work + B’s (x – 3) days work + C’s x days work = 1⇒ 2 × (1/10) + (x – 3) × 1/12 + x × (1/15) = 1⇒ 1/5 + (x -3)/12 + x/15 = 1(12 + 5x – 15 + 4x = 60)/60(L.C.M of 5, 12, 15 = 60)⇒ 9x = 60 – 12 + 15 ⇒ 9x = 63

A’s one day’s work = 1/10B’s one day’s work = 1/12C’s one day’s work = 1/15A, B and C’s one day’s work = 1/10 + 1/12 + 1/15= (6 + 5 + 4)/60 = 15/60 = ¼Let the work completed in x days∴ A’s 2 days work + B’s (x – 3) days work + C’s x days work = 1⇒ 2 × (1/10) + (x – 3) × 1/12 + x × (1/15) = 1⇒ 1/5 + (x -3)/12 + x/15 = 1(12 + 5x – 15 + 4x = 60)/60(L.C.M of 5, 12, 15 = 60)⇒ 9x = 60 – 12 + 15 ⇒ 9x = 63⇒ x = 63/9 = 7

A’s one day’s work = 1/10B’s one day’s work = 1/12C’s one day’s work = 1/15A, B and C’s one day’s work = 1/10 + 1/12 + 1/15= (6 + 5 + 4)/60 = 15/60 = ¼Let the work completed in x days∴ A’s 2 days work + B’s (x – 3) days work + C’s x days work = 1⇒ 2 × (1/10) + (x – 3) × 1/12 + x × (1/15) = 1⇒ 1/5 + (x -3)/12 + x/15 = 1(12 + 5x – 15 + 4x = 60)/60(L.C.M of 5, 12, 15 = 60)⇒ 9x = 60 – 12 + 15 ⇒ 9x = 63⇒ x = 63/9 = 7∴ Work will last for 7 days

Answer 2

Answer:

4 days

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