Question

a b c can do a piece of work in 15 12 20 days respectively they started the work together but C left after 2 days in how many days will the remaining work be completed by a and b​

Answer 1

Answer:

Step-by-step explanation:

one day's work =a+b+c =1/15+1/12+1/20=1/5

2 day's work of a,b,c together=2×1/5=2/5

Remaining work=1-2/5=3/5

Combine work of both a,b=1/15+1/12=3/20

The no. of days taken by a,b to finish the remaining work =3/5÷3/20=4

Anwer is 4

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