A,b,c can do a piece of work in 150 days,75 days,75/2 days respectively if all three work alternatively starting with a then b followed by c then how many days work completed
Answers
A takes 150 days to complete the work
so A's one day work = 1/150
B takes 75 days to complete the work
so B's one day work = 1/75 = 2 / 150
C takes 75/2 days to complete the work
so C's one day work = 2/75 = 4 / 150
on first day , A completes 1/150 work
on second day B adds 2/150 work
and on third day C adds 4/150 work
so after 3 days together their work is = 7/150
so 3 days -------- 7 / 150 work
30 days -------- 70 / 150 work
60 days -------- 140 / 150 work
63 days -------- 147 / 150 work
on 64 th day A adds 1/150 work
completed work becomes , 148/150
on 65 th day B adds 2/150 work
completed work becomes , 150/150
so in 65 days whole work complete.
Answer:
65 Days
Step-by-step explanation:
A,b,c can do a piece of work in 150 days,75 days,75/2 days respectively
A's 1 day work = 1/150
B's 1 day work = 1/75
C's 1 Day work = 2/75
A + B + C ' together 1 day work = 1/150 + 1/75 + 2/75
=(1/150)(1 + 2 + 4)
= 7/150
But as they do not work together but alternately
so 3 days works = 7/150
7/150 work is done in 3 days
1 work is done in = 3 / (7/150)
= 450/7
= 64.29 days
This time is on average basis of a b & c work
but for 63 days each a , b & c worked for 63/3 = 21 days but after that each person did not work equally
so work done in 21 * 3 = 63 days = (7/150) * 21 = 147/150
Work left after that = 1 - 147/150 = 3/150
in 64th day a worked = 1/150
so after 64th day work remained = 3/150 - 1/150 = 2/150 = 1/75
B's 1 day work = 1/75
So b complete work on 65th Day